Рекурентная формула Зейделя в координатной форме:
x1(k+1) = 0.800 * x1(k) + -0.100 * x2(k) + -0.300
x2(k+1) = -0.100 * x1(k+1) + 0.800 * x2(k) + -0.300
Проверим достаточное условие сходимости итерационной последовательности
|0.800| + |-0.100| = 0.900 < 1
|-0.100| + |0.800| = 0.900 < 1
q = 0.900
Начальное приближение: X0 = (-0.300, -0.300)T
Итерация 1
x1(1) = 0.800 * x1(0) + -0.100 * x2(0) + -0.300 = -0.240 + 0.030 + -0.300 = -0.510
x2(1) = -0.100 * x1(1) + 0.800 * x2(0) + -0.300 = 0.051 + -0.240 + -0.300 = -0.489
q/(1-q) = 0.900 / (1 - 0.900) = 9.000
E1 = q/(1-q)*max(0.210,0.189) = 9.000 * 0.189 = 1.701
Итерация 2
x1(2) = 0.800 * x1(1) + -0.100 * x2(1) + -0.300 = -0.408 + 0.049 + -0.300 = -0.659
x2(2) = -0.100 * x1(2) + 0.800 * x2(1) + -0.300 = 0.066 + -0.391 + -0.300 = -0.625
E2 = q/(1-q)*max(0.149,0.136) = 9.000 * 0.136 = 1.227
Итерация 3
x1(3) = 0.800 * x1(2) + -0.100 * x2(2) + -0.300 = -0.527 + 0.063 + -0.300 = -0.765
x2(3) = -0.100 * x1(3) + 0.800 * x2(2) + -0.300 = 0.076 + -0.500 + -0.300 = -0.724
E3 = q/(1-q)*max(0.106,0.098) = 9.000 * 0.098 = 0.886
Итерация 4
x1(4) = 0.800 * x1(3) + -0.100 * x2(3) + -0.300 = -0.612 + 0.072 + -0.300 = -0.839
x2(4) = -0.100 * x1(4) + 0.800 * x2(3) + -0.300 = 0.084 + -0.579 + -0.300 = -0.795
E4 = q/(1-q)*max(0.075,0.071) = 9.000 * 0.071 = 0.642
Итерация 5
x1(5) = 0.800 * x1(4) + -0.100 * x2(4) + -0.300 = -0.672 + 0.080 + -0.300 = -0.892
x2(5) = -0.100 * x1(5) + 0.800 * x2(4) + -0.300 = 0.089 + -0.636 + -0.300 = -0.847
E5 = q/(1-q)*max(0.053,0.052) = 9.000 * 0.052 = 0.466
Итерация 6
x1(6) = 0.800 * x1(5) + -0.100 * x2(5) + -0.300 = -0.714 + 0.085 + -0.300 = -0.929
x2(6) = -0.100 * x1(6) + 0.800 * x2(5) + -0.300 = 0.093 + -0.677 + -0.300 = -0.885
E6 = q/(1-q)*max(0.037,0.038) = 9.000 * 0.038 = 0.340
Итерация 7
x1(7) = 0.800 * x1(6) + -0.100 * x2(6) + -0.300 = -0.743 + 0.088 + -0.300 = -0.955
x2(7) = -0.100 * x1(7) + 0.800 * x2(6) + -0.300 = 0.095 + -0.708 + -0.300 = -0.912
E7 = q/(1-q)*max(0.026,0.028) = 9.000 * 0.028 = 0.249
Итерация 8
x1(8) = 0.800 * x1(7) + -0.100 * x2(7) + -0.300 = -0.764 + 0.091 + -0.300 = -0.973
x2(8) = -0.100 * x1(8) + 0.800 * x2(7) + -0.300 = 0.097 + -0.730 + -0.300 = -0.933
E8 = q/(1-q)*max(0.018,0.020) = 9.000 * 0.020 = 0.183
Итерация 9
x1(9) = 0.800 * x1(8) + -0.100 * x2(8) + -0.300 = -0.778 + 0.093 + -0.300 = -0.985
x2(9) = -0.100 * x1(9) + 0.800 * x2(8) + -0.300 = 0.098 + -0.746 + -0.300 = -0.948
E9 = q/(1-q)*max(0.012,0.015) = 9.000 * 0.015 = 0.135
Итерация 10
x1(10) = 0.800 * x1(9) + -0.100 * x2(9) + -0.300 = -0.788 + 0.095 + -0.300 = -0.993
x2(10) = -0.100 * x1(10) + 0.800 * x2(9) + -0.300 = 0.099 + -0.758 + -0.300 = -0.959
E10 = q/(1-q)*max(0.008,0.011) = 9.000 * 0.011 = 0.101
Итерация 11
x1(11) = 0.800 * x1(10) + -0.100 * x2(10) + -0.300 = -0.794 + 0.096 + -0.300 = -0.999
x2(11) = -0.100 * x1(11) + 0.800 * x2(10) + -0.300 = 0.100 + -0.767 + -0.300 = -0.967
E11 = q/(1-q)*max(0.006,0.008) = 9.000 * 0.008 = 0.076
Итерация 12
x1(12) = 0.800 * x1(11) + -0.100 * x2(11) + -0.300 = -0.799 + 0.097 + -0.300 = -1.002
x2(12) = -0.100 * x1(12) + 0.800 * x2(11) + -0.300 = 0.100 + -0.774 + -0.300 = -0.973
E12 = q/(1-q)*max(0.004,0.006) = 9.000 * 0.006 = 0.057
Итерация 13
x1(13) = 0.800 * x1(12) + -0.100 * x2(12) + -0.300 = -0.802 + 0.097 + -0.300 = -1.004
x2(13) = -0.100 * x1(13) + 0.800 * x2(12) + -0.300 = 0.100 + -0.779 + -0.300 = -0.978
E13 = q/(1-q)*max(0.002,0.005) = 9.000 * 0.005 = 0.044
E13 <= e
Ответ: X = (-1.004, -0.978)T
Проверка
0.200 * -1.004 + 0.100 * -0.978 = -0.201 + -0.098 = -0.299
0.100 * -1.004 + 0.200 * -0.978 = -0.100 + -0.196 = -0.296
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