08.04.2010, 19:36
общий
это ответ
Здравствуйте, Venya.
1. [$8747$](1/(arcSin2x)[$8730$](1-x2)dx = [$8747$](1/(arcSin2x)d(arcSin(x)) = -1/(arcSin(x))
2. [$8747$](x2+2x+3)Cos2xdx = [u=x2+2x+3 => du = (2x+2)dx; dv = Cos2xdx => v=1/2Sin2x] = 1/2(x2+2x+3)Sin2x - 1/2[$8747$](2x+2)Sin2xdx = [u=2x+2 => du=2dx; dv=Sin2xdx => v=-1/2Cos2x] = 1/2(x2+2x+3)Sin2x - 1/2(-(2x+2)Cos2x + 1/2[$8747$]2Cos2xdx) = 1/2(x2+2x+3)Sin2x + (x+1)Cos2x -1/4Sin2x