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Консультация № 182529
16.03.2011, 18:16
56.81 руб.
0
7
1
Уважаемые эксперты! Помогите, пожалуйста, решитьзадачу.
Первые потенциалы возбужд. Li и Na равны соответственно 1,8 и 2,1 эВ. При какой t средняя кинетическая энергия равна энергии возбуждения?
И еще очень нужна эта (повторяюсь)
При изменении обратного напряжения от 0,1 до 1 В на контакте Шоттки, изготовленном с использованием донорного полупроводника и металла, емкость контакта уменьшилась в 2 раза. Работа выхода из металла равна 4,4 эВ. Найти работу выхода из полупроводника.
Спасибо!
Первые потенциалы возбужд. Li и Na равны соответственно 1,8 и 2,1 эВ. При какой t средняя кинетическая энергия равна энергии возбуждения?
И еще очень нужна эта (повторяюсь)
При изменении обратного напряжения от 0,1 до 1 В на контакте Шоттки, изготовленном с использованием донорного полупроводника и металла, емкость контакта уменьшилась в 2 раза. Работа выхода из металла равна 4,4 эВ. Найти работу выхода из полупроводника.
Спасибо!
Обсуждение
Неизвестный
16.03.2011, 20:22
общий
Скажите, пожалуйта, из какого раздела эти задачи? Твердотельная электроника?
16.03.2011, 21:02
общий
Средняя кинетическая энергия чего имеется в виду в первой задаче? Электрона?
Об авторе:
Facta loquuntur.
Facta loquuntur.
16.03.2011, 22:01
общий
это ответ
Здравствуйте, alya_koshka!
Первую задачу, полагаю, можно решить следующим образом.
Потенциал возбуждения - это энергия возбуждения, выраженная в электрон-вольтах. Единицей измерения энергии в СИ является джоуль. Между джоулем и электрон-вольтом существует соотношение 1 эВ = 1,60 [$149$] 10-19 Дж. Поэтому энергия возбуждения для лития равна E = 1,8 [$149$] 1,60 [$149$] 10-19 (Дж), а для натрия равна E = 2,1 [$149$] 1,60 [$149$] 10-19 (Дж).
Средняя кинетическая энергия электронов равна 3kT/2, где k - постоянная Больцмана. Согласно условию задачи, имеем
, откуда 
что после вычислений даёт следующие величины температур:
- для лития
- для натрия
С уважением.
Первую задачу, полагаю, можно решить следующим образом.
Потенциал возбуждения - это энергия возбуждения, выраженная в электрон-вольтах. Единицей измерения энергии в СИ является джоуль. Между джоулем и электрон-вольтом существует соотношение 1 эВ = 1,60 [$149$] 10-19 Дж. Поэтому энергия возбуждения для лития равна E = 1,8 [$149$] 1,60 [$149$] 10-19 (Дж), а для натрия равна E = 2,1 [$149$] 1,60 [$149$] 10-19 (Дж).
Средняя кинетическая энергия электронов равна 3kT/2, где k - постоянная Больцмана. Согласно условию задачи, имеем
, откуда что после вычислений даёт следующие величины температур:- для лития
- для натрия
С уважением.
Об авторе:
Facta loquuntur.
Facta loquuntur.
Неизвестный
16.03.2011, 22:17
общий
Адресаты:
Скорее всего электрона. Условие дано именно так. Спасибо за решение.
16.03.2011, 22:33
общий
Вторая задача выходит за пределы моих познаний в физике. Надеюсь, что в рассылке найдётся эксперт, способный Вам помочь с её решением.
Об авторе:
Facta loquuntur.
Facta loquuntur.
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