15.11.2007, 17:40
общий
это ответ
Здравствуйте, Packbar!
x = sin(3t) + 2,
y = tg(3t) – 1.
dx/dt = 3cos(3t), dy/dt = 3/cos²3t,
dy/dx = (dy/dt)/(dx/dt) = 1/cos³3t;
d²y/(dxdt) = 9sin(3t)/cos<sup>4</sup>3t,
d²y/dx² = (d²y/(dxdt))/(dx/dt) = 3sin(3t)/cos<sup>5</sup>3t.
Ответ: d²y/dx² = 3sin(3t)/cos<sup>5</sup>3t.