13.11.2007, 19:52
общий
это ответ
Здравствуйте, Павел Сергеевич!
1.
lim<sub>x→0</sub>(x<sup>6</sup>-7x<sup>4</sup>+x+9)/(3-4x<sup>7</sup>) = (0<sup>6</sup>-7*0<sup>4</sup>+0+9)/(3-4*0<sup>7</sup>) = 9/3 = 3.
2.
lim<sub>x→-1</sub>(4x<sup>4</sup>+3x-1)/(x<sup>4</sup>+2x<sup>3</sup>+1) = lim<sub>x→-1</sub>(x+1)(4x³-4x²+4x-1)/((x+1)(x³+x²-x+1)) = lim<sub>x→-1</sub>(4x³-4x²+4x-1)/(x³+x²-x+1) = (-4-4-4-1)/(-1+1+1+1) = -13/2.