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Консультация № 169037
06.06.2009, 13:38
0.00 руб.
0
4
2
Здравствуйте!
Помогите, пожалуйста, решить задачки:
1) Определить молярную массу газа, свойства которого соответствуют свойствам смеси 160 г кислорода и 120 г азота.
2) В закрытом сосуде объемом 2 л находится азот, плотность которого 1,4 кг/м3. Какое количество теплоты надо сообщить азоту, чтобы нагреть его на 100 К? На сколько увеличится внутренняя энергия азота?
Заранее спасибо
Помогите, пожалуйста, решить задачки:
1) Определить молярную массу газа, свойства которого соответствуют свойствам смеси 160 г кислорода и 120 г азота.
2) В закрытом сосуде объемом 2 л находится азот, плотность которого 1,4 кг/м3. Какое количество теплоты надо сообщить азоту, чтобы нагреть его на 100 К? На сколько увеличится внутренняя энергия азота?
Заранее спасибо
Обсуждение
06.06.2009, 20:54
общий
2.
Дано:
(N2)
V=2 л =2е-3 м^3
p(ро-греч.буква)=1,4 кг/м^3
ДТ = 100 К (Д - дельта)
Найти: Q, ДU
Решение:
Поскольку процесс при постоянном объёме, то Q=ДU
ДU=i/2 * m/M * R *ДТ, где m=p*V, M = 28e-3 кг/моль - иолярная масса азота, R=8.31 Дж/моль*К - универс.газовая постоянная, i = 5 - число тепеней свободы молекулы азота.
ДU = 5/2 * 1.4*2e-3/28e-3 * 8.31 * 100 = 207.8 Дж
Q = ДU = 207.8 Дж
Дано:
(N2)
V=2 л =2е-3 м^3
p(ро-греч.буква)=1,4 кг/м^3
ДТ = 100 К (Д - дельта)
Найти: Q, ДU
Решение:
Поскольку процесс при постоянном объёме, то Q=ДU
ДU=i/2 * m/M * R *ДТ, где m=p*V, M = 28e-3 кг/моль - иолярная масса азота, R=8.31 Дж/моль*К - универс.газовая постоянная, i = 5 - число тепеней свободы молекулы азота.
ДU = 5/2 * 1.4*2e-3/28e-3 * 8.31 * 100 = 207.8 Дж
Q = ДU = 207.8 Дж
Об авторе:
С уважением
shvetski
С уважением
shvetski
06.06.2009, 20:55
общий
это ответ
Здравствуйте, zet1999.
2.
Дано:
(N2)
V=2 л =2е-3 м^3
p(ро-греч.буква)=1,4 кг/м^3
ДТ = 100 К (Д - дельта)
Найти: Q, ДU
Решение:
Поскольку процесс при постоянном объёме, то Q=ДU
ДU=i/2 * m/M * R *ДТ, где m=p*V, M = 28e-3 кг/моль - иолярная масса азота, R=8.31 Дж/моль*К - универс.газовая постоянная, i = 5 - число тепеней свободы молекулы азота.
ДU = 5/2 * 1.4*2e-3/28e-3 * 8.31 * 100 = 207.8 Дж
Q = ДU = 207.8 Дж
2.
Дано:
(N2)
V=2 л =2е-3 м^3
p(ро-греч.буква)=1,4 кг/м^3
ДТ = 100 К (Д - дельта)
Найти: Q, ДU
Решение:
Поскольку процесс при постоянном объёме, то Q=ДU
ДU=i/2 * m/M * R *ДТ, где m=p*V, M = 28e-3 кг/моль - иолярная масса азота, R=8.31 Дж/моль*К - универс.газовая постоянная, i = 5 - число тепеней свободы молекулы азота.
ДU = 5/2 * 1.4*2e-3/28e-3 * 8.31 * 100 = 207.8 Дж
Q = ДU = 207.8 Дж
Об авторе:
С уважением
shvetski
С уважением
shvetski
Неизвестный
08.06.2009, 01:12
общий
это ответ
Здравствуйте, zet1999.
1) Определить молярную массу газа
M=?, свойства которого соответствуют свойствам смеси
m1= 160 г
кислорода
M1= 32 г/моль и
m2= 120 г
азота
M2= 28 г/моль.
___
M= молярный вес, лучше обозначить - мю малое
___
Всего имеем вещества в количестве
N= (m1/M1)+(m2/M2)= 160/32+ 120/28= 9,286 моль
масса этого вещества
m= m1+m2= 160+ 120= 280 г
следовательно эквивалентная молярная масса смеси
M= m/N= 280/9.286= 30,2 г/моль
1) Определить молярную массу газа
M=?, свойства которого соответствуют свойствам смеси
m1= 160 г
кислорода
M1= 32 г/моль и
m2= 120 г
азота
M2= 28 г/моль.
___
M= молярный вес, лучше обозначить - мю малое
___
Всего имеем вещества в количестве
N= (m1/M1)+(m2/M2)= 160/32+ 120/28= 9,286 моль
масса этого вещества
m= m1+m2= 160+ 120= 280 г
следовательно эквивалентная молярная масса смеси
M= m/N= 280/9.286= 30,2 г/моль
Форма ответа
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